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no_life's blog. Stars and bars modified. By no_life , history , 4 years ago , We all know that the number of solutions to a+b = 3 (where a and b are non negative) can be easily found out by stars and bars theorem. So answer of the above is 4. { (3,0), (0,3), (1,2), (2,1)}. But I want the answer to be 2 as the first two and last two are equivalent.. "/>